用 SQLite 做数据持久化

目录

如果您正在编写一个需要持久化且查询大量本地设备数据的 app，可考虑采用数据库，而不是本地文件夹或关键值库。总的来说，相比于其他本地持久化方案来说，数据库能够提供更为迅速的插入、更新、查询功能。

If you are writing an app that needs to persist and query large amounts of data on the local device, consider using a database instead of a local file or key-value store. In general, databases provide faster inserts, updates, and queries compared to other local persistence solutions.

Flutter应用程序中可以通过 sqflite package 来使用 SQLite 数据库。本文将通过使用 sqflite 来演示插入，读取，更新，删除各种狗狗的数据。

Flutter apps can make use of the SQLite databases via the sqflite plugin available on pub.dev. This recipe demonstrates the basics of using sqflite to insert, read, update, and remove data about various Dogs.

如果你对于 SQLite 和 SQL 的各种语句还不熟悉，请查看 SQLite 官方的教程 SQLite 教程，在查看本文之前需要掌握基本的SQL语句。

If you are new to SQLite and SQL statements, review the SQLite Tutorial to learn the basics before completing this recipe.

步骤：

This recipe uses the following steps:

  1. 添加依赖
  2. 定义 Dog（狗） 数据模型；
  3. 打开数据库；
  4. 创建 dogs 数据表；
  5. 将一条 Dog 数据插入数据库；
  6. 查询所有狗狗的数据；
  7. 更新（修改）一条 Dog 的数据；
  8. 删除一条 Dog 的数据。

1. 添加依赖

1. Add the dependencies

为了使用 SQLite 数据库，首先需要导入 sqflite 和 path 这两个 package。

To work with SQLite databases, import the sqflite and path packages.

  • sqflite 提供了丰富的类和方法，以便你能便捷实用 SQLite 数据库。

    The sqflite package provides classes and functions to interact with a SQLite database.

  • path 提供了大量方法，以便你能正确的定义数据库在磁盘上的存储位置。

    The path package provides functions to define the location for storing the database on disk.

dependencies:
  flutter:
    sdk: flutter
  sqflite:
  path:

确保你已将 packages 导入要使用的文件中。

Make sure to import the packages in the file you’ll be working in.

import 'dart:async';

import 'package:path/path.dart';
import 'package:sqflite/sqflite.dart';

2. 定义狗狗的数据模型

2. Define the Dog data model

在你准备在新建的表里存储狗狗们的信息的的时候，你需要先定义这些数据。例如，定义一个狗类时，每一条狗狗的数据将包含三个字段：一个唯一的 id ；名字 name ；年龄 age。

Before creating the table to store information on Dogs, take a few moments to define the data that needs to be stored. For this example, define a Dog class that contains three pieces of data: A unique id, the name, and the age of each dog.

class Dog {
  final int id;
  final String name;
  final int age;

  const Dog({
    required this.id,
    required this.name,
    required this.age,
  });
}

3. 打开数据库

3. Open the database

在你准备读写数据库的数据之前，你要先打开这个数据库。打开一个数据库有以下两个步骤：

Before reading and writing data to the database, open a connection to the database. This involves two steps:

  1. 使用 sqflite package 里的 getDatabasesPath 方法并配合 path package里的 join 方法定义数据库的路径。

    Define the path to the database file using getDatabasesPath() from the sqflite package, combined with the join function from the path package.

  2. Open the database with the openDatabase() function from sqflite.

使用 sqflite package 里的 openDatabase 方法打开数据库。 
// Avoid errors caused by flutter upgrade.
// Importing 'package:flutter/widgets.dart' is required.
WidgetsFlutterBinding.ensureInitialized();
// Open the database and store the reference.
final database = openDatabase(
  // Set the path to the database. Note: Using the `join` function from the
  // `path` package is best practice to ensure the path is correctly
  // constructed for each platform.
  join(await getDatabasesPath(), 'doggie_database.db'),
);

4. 创建 dogs 表

4. Create the dogs table

接下来，你需要创建一个表用以存储各种狗狗的信息。在这个示例中，创建一个名为 dogs 数据库表，它定义了可以被存储的数据。这样，每条 Dog 数据就包含了一个 id， name 和 age。因此，在 dogs 数据库表中将有三列，分别是 id， name 和 age。

Next, create a table to store information about various Dogs. For this example, create a table called dogs that defines the data that can be stored. Each Dog contains an id, name, and age. Therefore, these are represented as three columns in the dogs table.

  1. id 是 Dart 的 int 类型，在数据表中是 SQLite 的 INTEGER 数据类型。最佳实践是将 id 作为数据库表的主键，用以改善查询和修改的时间。

    The id is a Dart int, and is stored as an INTEGER SQLite Datatype. It is also good practice to use an id as the primary key for the table to improve query and update times.

  2. name 是Dart的 String类型，在数据表中是SQLite的 TEXT 数据类型。

    The name is a Dart String, and is stored as a TEXT SQLite Datatype.

  3. age 也是Dart的 int 类型，在数据表中是SQLite的 INTEGER 数据类型。

    The age is also a Dart int, and is stored as an INTEGER Datatype.

关于 SQLite 数据库能够存储的更多的数据类型信息请查阅官方的 SQLite Datatypes 文档。

For more information about the available Datatypes that can be stored in a SQLite database, see the official SQLite Datatypes documentation.

final database = openDatabase(
  // Set the path to the database. Note: Using the `join` function from the
  // `path` package is best practice to ensure the path is correctly
  // constructed for each platform.
  join(await getDatabasesPath(), 'doggie_database.db'),
  // When the database is first created, create a table to store dogs.
  onCreate: (db, version) {
    // Run the CREATE TABLE statement on the database.
    return db.execute(
      'CREATE TABLE dogs(id INTEGER PRIMARY KEY, name TEXT, age INTEGER)',
    );
  },
  // Set the version. This executes the onCreate function and provides a
  // path to perform database upgrades and downgrades.
  version: 1,
);

5. 插入一条狗狗的数据

5. Insert a Dog into the database

现在你已经准备好了一个数据库用于存储各种狗狗的信息数据，现在开始读写数据咯。

Now that you have a database with a table suitable for storing information about various dogs, it’s time to read and write data.

首先，在 dogs 数据表中插入一条 Dog 数据。分以下两步：

First, insert a Dog into the dogs table. This involves two steps:

  1. 把 Dog 转换成一个 Map 数据类型；

    Convert the Dog into a Map

  2. 使用 insert() 方法把 Map 保存到 dogs 数据表中。

    Use the insert() method to store the Map in the dogs table.

class Dog {
  final int id;
  final String name;
  final int age;

  const Dog({
    required this.id,
    required this.name,
    required this.age,
  });

  // Convert a Dog into a Map. The keys must correspond to the names of the
  // columns in the database.
  Map<String, dynamic> toMap() {
    return {
      'id': id,
      'name': name,
      'age': age,
    };
  }

  // Implement toString to make it easier to see information about
  // each dog when using the print statement.
  @override
  String toString() {
    return 'Dog{id: $id, name: $name, age: $age}';
  }
}
// Define a function that inserts dogs into the database
Future<void> insertDog(Dog dog) async {
  // Get a reference to the database.
  final db = await database;

  // Insert the Dog into the correct table. You might also specify the
  // `conflictAlgorithm` to use in case the same dog is inserted twice.
  //
  // In this case, replace any previous data.
  await db.insert(
    'dogs',
    dog.toMap(),
    conflictAlgorithm: ConflictAlgorithm.replace,
  );
}
// Create a Dog and add it to the dogs table
var fido = const Dog(
  id: 0,
  name: 'Fido',
  age: 35,
);

await insertDog(fido);

6. 查询狗狗列表

6. Retrieve the list of Dogs

现在已经有了一条 Dog 存储在数据库里。你可以通过查询数据库，检索到一只狗狗的数据或者所有狗狗的数据。分为以下两步:

Now that a Dog is stored in the database, query the database for a specific dog or a list of all dogs. This involves two steps:

  1. 调用 dogs 表对像的 query 方法。这将返回一个List <Map>。

    Run a query against the dogs table. This returns a List<Map>.

  2. 将 List<Map> 转换成 List<Dog> 数据类型。

    Convert the List<Map> into a List<Dog>.

// A method that retrieves all the dogs from the dogs table.
Future<List<Dog>> dogs() async {
  // Get a reference to the database.
  final db = await database;

  // Query the table for all The Dogs.
  final List<Map<String, dynamic>> maps = await db.query('dogs');

  // Convert the List<Map<String, dynamic> into a List<Dog>.
  return List.generate(maps.length, (i) {
    return Dog(
      id: maps[i]['id'],
      name: maps[i]['name'],
      age: maps[i]['age'],
    );
  });
}
// Now, use the method above to retrieve all the dogs.
print(await dogs()); // Prints a list that include Fido.

7. 修改一条 Dog 数据

7. Update a Dog in the database

使用 sqflite package 中的 update()方法，可以对已经插入到数据库中的数据进行修改（更新）。

After inserting information into the database, you might want to update that information at a later time. You can do this by using the update() method from the sqflite library.

修改数据操作包含以下两步：

This involves two steps:

  1. 将一条狗狗的数据转换成 Map 数据类型；

    Convert the Dog into a Map.

  2. 使用 where 语句定位到具体将要被修改的数据。

    Use a where clause to ensure you update the correct Dog.

Future<void> updateDog(Dog dog) async {
  // Get a reference to the database.
  final db = await database;

  // Update the given Dog.
  await db.update(
    'dogs',
    dog.toMap(),
    // Ensure that the Dog has a matching id.
    where: 'id = ?',
    // Pass the Dog's id as a whereArg to prevent SQL injection.
    whereArgs: [dog.id],
  );
}
// Update Fido's age and save it to the database.
fido = Dog(
  id: fido.id,
  name: fido.name,
  age: fido.age + 7,
);
await updateDog(fido);

// Print the updated results.
print(await dogs()); // Prints Fido with age 42.

8. 删除一条 Dog 的数据

8. Delete a Dog from the database

除了插入和修改狗狗们的数据，你还可以从数据库中删除狗狗的数据。删除数据用到了 sqflite package 中的 delete() 方法。

In addition to inserting and updating information about Dogs, you can also remove dogs from the database. To delete data, use the delete() method from the sqflite library.

在这一小节，新建一个方法用来接收一个 id 并且删除数据库中与这个 id 匹配的那一条数据。为了达到这个目的，你必须使用 where 语句限定哪一条才是被删除的数据。

In this section, create a function that takes an id and deletes the dog with a matching id from the database. To make this work, you must provide a where clause to limit the records being deleted.

Future<void> deleteDog(int id) async {
  // Get a reference to the database (获得数据库引用)
  final db = await database;

  // Remove the Dog from the database.
  await db.delete(
    'dogs',
    // Use a `where` clause to delete a specific dog.
    where: 'id = ?',
    // Pass the Dog's id as a whereArg to prevent SQL injection.
    whereArgs: [id],
  );
}

示例

Example

运行示例需要以下几步：

To run the example:

  1. 创建一个新的 Flutter 工程；

    Create a new Flutter project.

  2. 将 sqflite 和 path 包添加到 pubspec.yaml 文件里；

    Add the sqflite and path packages to your pubspec.yaml.

  3. 将以下代码粘贴在 lib/db_test.dart 文件里（若无则新建，若有则覆盖）；

    Paste the following code into a new file called lib/db_test.dart.

  4. 运行 flutter run lib/db_test.dart。

    Run the code with flutter run lib/db_test.dart.

import 'dart:async';

import 'package:path/path.dart';
import 'package:sqflite/sqflite.dart';
import 'package:flutter/widgets.dart';

void main() async {
  // Avoid errors caused by flutter upgrade.
  // Importing 'package:flutter/widgets.dart' is required.
  WidgetsFlutterBinding.ensureInitialized();
  // Open the database and store the reference.
  final database = openDatabase(
    // Set the path to the database. Note: Using the `join` function from the
    // `path` package is best practice to ensure the path is correctly
    // constructed for each platform.
    // 设置数据库的路径。注意：使用 `path` 包中的 `join` 方法是
    // 确保在多平台上路径都正确的最佳实践。
    join(await getDatabasesPath(), 'doggie_database.db'),
    // When the database is first created, create a table to store dogs.
    // 当数据库第一次被创建的时候，创建一个数据表，用以存储狗狗们的数据。
    onCreate: (db, version) {
      // Run the CREATE TABLE statement on the database.
      return db.execute(
        'CREATE TABLE dogs(id INTEGER PRIMARY KEY, name TEXT, age INTEGER)',
      );
    },
    // Set the version. This executes the onCreate function and provides a
    // path to perform database upgrades and downgrades.
    // 设置版本。它将执行 onCreate 方法，同时提供数据库升级和降级的路径。
    version: 1,
  );

  // Define a function that inserts dogs into the database
  Future<void> insertDog(Dog dog) async {
    // Get a reference to the database.
    final db = await database;

    // Insert the Dog into the correct table. You might also specify the
    // `conflictAlgorithm` to use in case the same dog is inserted twice.
    //
    // In this case, replace any previous data.
    await db.insert(
      'dogs',
      dog.toMap(),
      conflictAlgorithm: ConflictAlgorithm.replace,
    );
  }

  // A method that retrieves all the dogs from the dogs table.
  Future<List<Dog>> dogs() async {
    // Get a reference to the database.
    final db = await database;

    // Query the table for all The Dogs.
    final List<Map<String, dynamic>> maps = await db.query('dogs');
    // Convert the List<Map<String, dynamic> into a List<Dog> (将 List<Map<String, dynamic> 转换成 List<Dog> 数据类型)
    return List.generate(maps.length, (i) {
      return Dog(
        id: maps[i]['id'],
        name: maps[i]['name'],
        age: maps[i]['age'],
      );
    });
  }

  Future<void> updateDog(Dog dog) async {
    // Get a reference to the database (获得数据库引用)
    final db = await database;
    // Update the given Dog (修改给定的狗狗的数据)
    await db.update(
      'dogs',
      dog.toMap(),
      // Ensure that the Dog has a matching id.
      where: 'id = ?',
      // Pass the Dog's id as a whereArg to prevent SQL injection.
      whereArgs: [dog.id],
    );
  }

  Future<void> deleteDog(int id) async {
    // Get a reference to the database (获得数据库引用)
    final db = await database;
    // Remove the Dog from the database (将狗狗从数据库移除)
    await db.delete(
      'dogs',
      // Use a `where` clause to delete a specific dog.
      where: 'id = ?',
      // Pass the Dog's id as a whereArg to prevent SQL injection.
      whereArgs: [id],
    );
  }

  // Create a Dog and add it to the dogs table
  var fido = const Dog(
    id: 0,
    name: 'Fido',
    age: 35,
  );

  await insertDog(fido);

  // Now, use the method above to retrieve all the dogs.
  print(await dogs()); // Prints a list that include Fido.

  // Update Fido's age and save it to the database.
  fido = Dog(
    id: fido.id,
    name: fido.name,
    age: fido.age + 7,
  );
  await updateDog(fido);

  // Print the updated results.
  print(await dogs()); // Prints Fido with age 42.

  // Delete Fido from the database.
  await deleteDog(fido.id);
  // Print the list of dogs (empty) [打印一个列表的狗狗们 (这里已经空了)]
  print(await dogs());
}

class Dog {
  final int id;
  final String name;
  final int age;

  const Dog({
    required this.id,
    required this.name,
    required this.age,
  });

  // Convert a Dog into a Map. The keys must correspond to the names of the
  // columns in the database.
  Map<String, dynamic> toMap() {
    return {
      'id': id,
      'name': name,
      'age': age,
    };
  }

  // Implement toString to make it easier to see information about
  // each dog when using the print statement.
  // 重写 toString 方法，以便使用 print 方法查看每个狗狗信息的时候能更清晰。
  @override
  String toString() {
    return 'Dog{id: $id, name: $name, age: $age}';
  }
}